A proton moves perpendicular to B=0.1 T field at 10 6 m/s. Radius of circular path (m p = 1.67 x 10 -27 kg, e = 1.6 x 10 -19 C):

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A proton moves perpendicular to B=0.1 T field at 106 m/s. Radius of circular path (mp = 1.67 x 10-27 kg, e = 1.6 x 10-19 C):

Answer: 0.104 m.

A 0.104 m
B 1.04 m
C 10.4 m
D 0.01 m

Correct answer: A. 0.104 m

Explanation: r = mv/(qB) = 1.67x10-27 x 106 / (1.6x10-19 x 0.1) = 1.67x10-21 / 1.6x10-20 = 0.104 m.

The magnetic field around a long straight current-carrying wire forms concentric circles, with direction given by the right-hand rule (point thumb along I, fingers curl in the direction of B).

Concept context

Magnetic force on moving charges and currents, the Biot-Savart law, Ampere's law, and the cyclotron - how electric currents create and respond to magnetic fields.

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A proton moves perpendicular to B=0.1 T field at 10<sup>6</sup> m/s. Radius of circular path (m<sub>p</sub> = 1.67 x 10<sup>-27</sup> kg, e = 1.6 x 10<sup>-19</sup> C):

Concept context

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