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⚛️ Physics  ·  Motion in a Straight Line  ·  NEET & JEE

A stone is thrown vertically up at 30 m/s (g = 10 m/s²). The time interval between the two instants when it is at a height of 40 m is:

Answer: 2 s.

  • A 1 s
  • B 2 s
  • C 3 s
  • D 4 s

Correct answer: B. 2 s

Explanation: 40 = 30t − 5t² → t² − 6t + 8 = 0 → t = 2 s and 4 s; interval = 2 s.

tvuvTΔtΔvslope = aarea = displacement (s)

On a velocity-time graph for uniform acceleration, the slope of the line gives the acceleration and the shaded area under the line gives the displacement.

Concept context

Equations of motion, projectile motion, relative velocity. Foundation of all mechanics.

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