A particle moves with position x = 2t 3 - 3t 2 + 4t (SI units). Its velocity at the instant its acceleration is zero is:

⚛️ Physics · Motion in a Straight Line · NEET & JEE

A particle moves with position x = 2t3 - 3t2 + 4t (SI units). Its velocity at the instant its acceleration is zero is:

Answer: 2.5 m s -1.

A 1.5 m s-1
B 3.5 m s-1
C 2.5 m s-1
D 4 m s-1

Correct answer: C. 2.5 m s-1

Explanation: v = 6t2 - 6t + 4 and a = 12t - 6 = 0 gives t = 0.5 s. Then v = 6(0.25) - 6(0.5) + 4 = 1.5 - 3 + 4 = 2.5 m s-1.

On a velocity-time graph for uniform acceleration, the slope of the line gives the acceleration and the shaded area under the line gives the displacement.

Concept context

Equations of motion, projectile motion, relative velocity. Foundation of all mechanics.

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A particle moves with position x = 2t<sup>3</sup> - 3t<sup>2</sup> + 4t (SI units). Its velocity at the instant its acceleration is zero is:

Concept context

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