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⚛️ Physics  ·  Motion in a Straight Line  ·  NEET & JEE

A body moving at 20 m/s decelerates uniformly at 2 m/s². The distance it covers during the 6th second of its motion is:

Answer: 9 m.

  • A 9 m
  • B 11 m
  • C 10 m
  • D 8 m

Correct answer: A. 9 m

Explanation: s<sub>6th</sub> = u + a(n − 0.5) = 20 + (−2)(5.5) = 9 m (body stops at t = 10 s, so still moving).

tvuvTΔtΔvslope = aarea = displacement (s)

On a velocity-time graph for uniform acceleration, the slope of the line gives the acceleration and the shaded area under the line gives the displacement.

Concept context

Equations of motion, projectile motion, relative velocity. Foundation of all mechanics.

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