Zaymiey

⚛️ Physics  ·  Motion in a Straight Line  ·  NEET & JEE

A ball thrown vertically upward with speed 25 m s<sup>-1</sup> returns to the point of projection after (g = 10 m s<sup>-2</sup>):

Answer: 5 s.

  • A 2.5 s
  • B 7.5 s
  • C 5 s
  • D 10 s

Correct answer: C. 5 s

Explanation: Total time of flight = 2u/g = 2 × 25 / 10 = 5 s.

tvuvTΔtΔvslope = aarea = displacement (s)

On a velocity-time graph for uniform acceleration, the slope of the line gives the acceleration and the shaded area under the line gives the displacement.

Concept context

Equations of motion, projectile motion, relative velocity. Foundation of all mechanics.

Read the full Motion in a Straight Line notes →