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⚛️ Physics  ·  Motion in a Straight Line  ·  NEET & JEE

A ball thrown horizontally at 20 m/s from height h hits ground at 45° angle. h = (g=10):

Answer: 20 m.

  • A 10 m
  • B 20 m
  • C 30 m
  • D 40 m

Correct answer: B. 20 m

Explanation: At ground, vy/vx = tan45° = 1, so vy = vx = 20 m/s. vy = gt → t=2 s. h = ½gt² = ½×10×4 = 20 m.

tvuvTΔtΔvslope = aarea = displacement (s)

On a velocity-time graph for uniform acceleration, the slope of the line gives the acceleration and the shaded area under the line gives the displacement.

Concept context

Equations of motion, projectile motion, relative velocity. Foundation of all mechanics.

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