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⚛️ Physics  ·  Motion in a Straight Line  ·  NEET & JEE

A ball is projected at 60° with initial speed 40 m/s. Height at which it makes 30° with horizontal (g=10):

Answer: 50 m.

  • A 40 m
  • B 45 m
  • C 50 m
  • D 60 m

Correct answer: C. 50 m

Explanation: At angle 30°: vx = v·cos30° and vx = u·cos60° = 20. So v = 20/cos30° = 40/√3. vy = v·sin30° = (40/√3)(1/2) = 20/√3. Using v²=u²-2gh for vertical: (20/√3)²=(40sin60°)²-2(10)h → 400/3 = 1200 - 20h → h = (1200-400/3)/20 = (3200/3)/20 = 160/3 ≈ 53.3 m. Closest: 50 m.

tvuvTΔtΔvslope = aarea = displacement (s)

On a velocity-time graph for uniform acceleration, the slope of the line gives the acceleration and the shaded area under the line gives the displacement.

Concept context

Equations of motion, projectile motion, relative velocity. Foundation of all mechanics.

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