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⚛️ Physics  ·  Motion in a Straight Line  ·  NEET & JEE

A ball is dropped from rest and travels 25 m in the last second of its fall (g = 10 m/s²). The total height of fall is:

Answer: 45 m.

  • A 45 m
  • B 50 m
  • C 40 m
  • D 55 m

Correct answer: A. 45 m

Explanation: Distance in last second = g(t − 0.5) = 25 → t = 3 s; height = (1/2)(10)(9) = 45 m.

tvuvTΔtΔvslope = aarea = displacement (s)

On a velocity-time graph for uniform acceleration, the slope of the line gives the acceleration and the shaded area under the line gives the displacement.

Concept context

Equations of motion, projectile motion, relative velocity. Foundation of all mechanics.

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