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⚛️ Physics  ·  Mechanical Properties of Solids  ·  NEET & JEE

A uniform wire of length L and cross-section A hangs vertically under its own weight (density ρ). The total elongation due to its own weight is:

Answer: ρgL²/(2Y).

  • A ρgL²/(2Y)
  • B ρgL²/Y
  • C 2ρgL²/Y
  • D ρgL/(2Y)

Correct answer: A. ρgL²/(2Y)

Explanation: For a hanging wire under its own weight, integrate the varying tension along the length: total elongation = ρgL²/(2Y), half of what it would be if the full weight acted uniformly.

Stress-Strain Curve for a Ductile Metal WireStrainStresselastic limityield pointUTS (max stress)fractureSlope of the straight (elastic) portion = Young's modulus Y; the curve beyond elastic limit shows permanent (plastic) deformation

A typical stress-strain curve: the initial straight line (Hooke's Law region, slope = Young's modulus) ends at the elastic limit; beyond the yield point, deformation becomes permanent, peaking at the ultimate tensile strength before the wire finally fractures.

Concept context

Stress, strain, Hookes law, and the elastic moduli that describe how solids deform and recover under load.

Read the full Mechanical Properties of Solids notes →