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⚛️ Physics  ·  Mechanical Properties of Fluids  ·  NEET & JEE

A sphere of density ρ_s, radius r, falls in a liquid of density ρ_l and viscosity η. At terminal velocity, the coefficient of viscosity is:

Answer: η = 2r²(ρ_s - ρ_l)g/9v t.

  • A η = 2r²(ρ_s - ρ_l)g/9v<sub>t</sub>
  • B η = 9v<sub>t</sub>/(2r² g) in standard practice
  • C η = 6πrv_t under most conditions encountered
  • D η = 2r² v<sub>t</sub> as frequently observed in practice

Correct answer: A. η = 2r²(ρ_s - ρ_l)g/9v<sub>t</sub>

Explanation: Stokes: v<sub>t</sub> = 2r²(ρ_s - ρ_l)g/(9η). Rearranging: η = 2r²(ρ_s - ρ_l)g/(9v<sub>t</sub>). This is how viscometry works experimentally.

Continuity Equation: Narrow Pipe → Faster FlowA₁, v₁ (wide, slow)A₂, v₂ (narrow, fast)A₁v₁ = A₂v₂ (continuity)Smaller area → higher speed → (by Bernoulli) LOWER pressure

Since the same volume of fluid must pass every cross-section per second (continuity), the fluid speeds up where the pipe narrows; Bernoulli's equation then says this faster-moving fluid has lower pressure - the principle behind a venturi meter and an aircraft wing's lift.

Concept context

Pressure, buoyancy, Bernoulli equation, viscosity, and surface tension.

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