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⚛️ Physics  ·  Magnetism and Matter  ·  NEET & JEE

At a place the horizontal component of Earth's field is 0.26 &times; 10<sup>-4</sup> T and the angle of dip is 60&deg;. The total field is:

Answer: 0.52 10 -4 T.

  • A 0.26 &times; 10<sup>-4</sup> T
  • B 0.30 &times; 10<sup>-4</sup> T
  • C 0.45 &times; 10<sup>-4</sup> T
  • D 0.52 &times; 10<sup>-4</sup> T

Correct answer: D. 0.52 &times; 10<sup>-4</sup> T

Explanation: B<sub>H</sub> = B cos&delta;, so B = B<sub>H</sub>/cos60 = 0.26 &times; 10<sup>-4</sup>/0.5 = 0.52 &times; 10<sup>-4</sup> T.

Magnetic field lines of a bar magnet, emerging from the north pole and curving round to enter the south pole outside the magnet

Magnetic field of a bar magnet: field lines emerge from the north pole and re-enter at the south pole outside the magnet, forming continuous closed loops. Image: Geek3, CC BY-SA 3.0, via Wikimedia Commons.

Concept context

Bar magnets, Earth's magnetism, and how different materials respond to an external magnetic field - diamagnetic, paramagnetic, and ferromagnetic behaviour.

Read the full Magnetism and Matter notes →