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⚛️ Physics  ·  Magnetism and Matter  ·  NEET & JEE

A short bar magnet of moment 0.4 A m<sup>2</sup> gives an axial (end-on) field at 0.2 m of (&mu;<sub>0</sub>/4&pi; = 10<sup>-7</sup>):

Answer: 1 10 -5 T.

  • A 2.5 &times; 10<sup>-6</sup> T
  • B 5 &times; 10<sup>-6</sup> T
  • C 1 &times; 10<sup>-5</sup> T
  • D 2 &times; 10<sup>-5</sup> T

Correct answer: C. 1 &times; 10<sup>-5</sup> T

Explanation: B<sub>axial</sub> = (&mu;<sub>0</sub>/4&pi;)(2m/r<sup>3</sup>) = 10<sup>-7</sup> &times; (2 &times; 0.4)/(0.2)<sup>3</sup> = 10<sup>-7</sup> &times; 0.8/0.008 = 1 &times; 10<sup>-5</sup> T.

Magnetic field lines of a bar magnet, emerging from the north pole and curving round to enter the south pole outside the magnet

Magnetic field of a bar magnet: field lines emerge from the north pole and re-enter at the south pole outside the magnet, forming continuous closed loops. Image: Geek3, CC BY-SA 3.0, via Wikimedia Commons.

Concept context

Bar magnets, Earth's magnetism, and how different materials respond to an external magnetic field - diamagnetic, paramagnetic, and ferromagnetic behaviour.

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