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⚛️ Physics  ·  Magnetism and Matter  ·  NEET & JEE

A short bar magnet of magnetic moment 0.5 J/T is placed at 30° with a uniform external magnetic field of 0.2 T. The torque acting on the magnet is approximately:

Answer: 0.05 N·m.

  • A 0.05 N·m
  • B 0.1 N·m
  • C 0.025 N·m
  • D 0.087 N·m

Correct answer: A. 0.05 N·m

Explanation: Torque τ = mB sin(θ) = 0.5 × 0.2 × sin(30°) = 0.1 × 0.5 = 0.05 N·m.

Bar Magnet Field LinesNSfield lines: N → S (outside magnet)

Magnetic field lines form closed loops: outside the bar magnet they run from the N pole to the S pole; inside, they continue from S back to N, so the lines never start or end anywhere.

Concept context

Bar magnets, Earth's magnetism, and how different materials respond to an external magnetic field - diamagnetic, paramagnetic, and ferromagnetic behaviour.

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