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⚛️ Physics  ·  Laws of Motion  ·  NEET & JEE

Two blocks of 3 kg and 2 kg are placed in contact on a frictionless surface. A horizontal force of 10 N is applied on the 3 kg block. The contact force between the blocks is:

Answer: 4 N.

  • A 4 N
  • B 6 N
  • C 10 N
  • D 2 N

Correct answer: A. 4 N

Explanation: Acceleration = 10/5 = 2 m/s²; contact force pushes the 2 kg block: F = 2·2 = 4 N.

incline surfaceθmgNfmg sinθmg cosθ

Free-body diagram of a block on an incline: weight (mg) resolves into mg sinθ along the slope and mg cosθ into the slope, balanced by the normal force N and friction f.

Concept context

Newton's three laws, friction, circular motion, and free body diagrams.

Read the full Laws of Motion notes →