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⚛️ Physics  ·  Laws of Motion  ·  NEET & JEE

If friction force is 40 N on a 10 kg block on a horizontal surface, coefficient of friction is (g=10):

Answer: 0.4.

  • A 0.2
  • B 0.3
  • C 0.4
  • D 0.5

Correct answer: C. 0.4

Explanation: mu = f / (mg) = 40 / (10 x 10) = 40/100 = 0.4.

incline surfaceθmgNfmg sinθmg cosθ

Free-body diagram of a block on an incline: weight (mg) resolves into mg sinθ along the slope and mg cosθ into the slope, balanced by the normal force N and friction f.

Concept context

Newton's three laws, friction, circular motion, and free body diagrams.

Read the full Laws of Motion notes →