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⚛️ Physics  ·  Laws of Motion  ·  NEET & JEE

Blocks m<sub>1</sub>=2 kg and m<sub>2</sub>=4 kg on rough surface mu=0.25. 18 N force pulls m<sub>1</sub> forward. Acceleration (g=10):

Answer: 0.5 m/s 2.

  • A 0.5 m/s<sup>2</sup>
  • B 1 m/s<sup>2</sup>
  • C 2 m/s<sup>2</sup>
  • D 3 m/s<sup>2</sup>

Correct answer: A. 0.5 m/s<sup>2</sup>

Explanation: Total friction = mu(m<sub>1</sub>+m<sub>2</sub>)g = 0.25 x 6 x 10 = 15 N. Net force = 18 - 15 = 3 N. a = 3/6 = 0.5 m/s<sup>2.</sup>

incline surfaceθmgNfmg sinθmg cosθ

Free-body diagram of a block on an incline: weight (mg) resolves into mg sinθ along the slope and mg cosθ into the slope, balanced by the normal force N and friction f.

Concept context

Newton's three laws, friction, circular motion, and free body diagrams.

Read the full Laws of Motion notes →