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⚛️ Physics  ·  Laws of Motion  ·  NEET & JEE

A person weighing 500 N is in a lift moving upward at constant velocity. The normal force exerted by floor is:

Answer: 500 N.

  • A Less than 500 N
  • B 500 N
  • C More than 500 N
  • D Zero

Correct answer: B. 500 N

Explanation: At constant velocity, a = 0. N = mg = 500 N. Weight feels normal.

incline surfaceθmgNfmg sinθmg cosθ

Free-body diagram of a block on an incline: weight (mg) resolves into mg sinθ along the slope and mg cosθ into the slope, balanced by the normal force N and friction f.

Concept context

Newton's three laws, friction, circular motion, and free body diagrams.

Read the full Laws of Motion notes →