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⚛️ Physics  ·  Laws of Motion  ·  NEET & JEE

A particle of mass m hits a fixed wall at speed v at angle 60 deg to normal and bounces off at 60 deg to normal. Coefficient of restitution is 1. Impulse magnitude:

Answer: mv.

  • A mv
  • B mv/2
  • C mv*sqrt(3)
  • D 2mv cos60

Correct answer: A. mv

Explanation: Only normal component reverses. Normal component = v cos60 = v/2. Impulse = 2m x v/2 = mv.

incline surfaceθmgNfmg sinθmg cosθ

Free-body diagram of a block on an incline: weight (mg) resolves into mg sinθ along the slope and mg cosθ into the slope, balanced by the normal force N and friction f.

Concept context

Newton's three laws, friction, circular motion, and free body diagrams.

Read the full Laws of Motion notes →