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⚛️ Physics  ·  Laws of Motion  ·  NEET & JEE

A man in lift reads W<sub>1</sub> when going up with acceleration a, and W<sub>2</sub> when going down with same acceleration a. His true weight is:

Answer: (W 1 + W 2 )/2.

  • A W<sub>1</sub> + W<sub>2</sub>
  • B (W<sub>1</sub> + W<sub>2</sub>)/2
  • C W<sub>1</sub> - W<sub>2</sub>
  • D (W<sub>1</sub> - W<sub>2</sub>)/2

Correct answer: B. (W<sub>1</sub> + W<sub>2</sub>)/2

Explanation: W<sub>1</sub> = m(g+a), W<sub>2</sub> = m(g-a). Adding: W<sub>1</sub>+W<sub>2</sub> = 2mg. True weight = mg = (W<sub>1</sub>+W<sub>2</sub>)/2.

incline surfaceθmgNfmg sinθmg cosθ

Free-body diagram of a block on an incline: weight (mg) resolves into mg sinθ along the slope and mg cosθ into the slope, balanced by the normal force N and friction f.

Concept context

Newton's three laws, friction, circular motion, and free body diagrams.

Read the full Laws of Motion notes →