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⚛️ Physics  ·  Laws of Motion  ·  NEET & JEE

A lift moving upward decelerates at 2 m s<sup>-2</sup>. The apparent weight of a 50 kg person in it is (g = 10 m s<sup>-2</sup>):

Answer: 400 N.

  • A 400 N
  • B 500 N
  • C 300 N
  • D 600 N

Correct answer: A. 400 N

Explanation: Decelerating while moving up means acceleration is downward, so N = m(g - a) = 50(10 - 2) = 400 N.

incline surfaceθmgNfmg sinθmg cosθ

Free-body diagram of a block on an incline: weight (mg) resolves into mg sinθ along the slope and mg cosθ into the slope, balanced by the normal force N and friction f.

Concept context

Newton's three laws, friction, circular motion, and free body diagrams.

Read the full Laws of Motion notes →