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⚛️ Physics  ·  Laws of Motion  ·  NEET & JEE

A 70 kg person stands in elevator accelerating upward at 3 m/s<sup>2.</sup> Normal force on person is (g=10):

Answer: 910 N.

  • A 490 N
  • B 630 N
  • C 700 N
  • D 910 N

Correct answer: D. 910 N

Explanation: N - mg = ma. N = m(g+a) = 70 x 13 = 910 N. Person feels heavier when elevator accelerates up.

incline surfaceθmgNfmg sinθmg cosθ

Free-body diagram of a block on an incline: weight (mg) resolves into mg sinθ along the slope and mg cosθ into the slope, balanced by the normal force N and friction f.

Concept context

Newton's three laws, friction, circular motion, and free body diagrams.

Read the full Laws of Motion notes →