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⚛️ Physics  ·  Laws of Motion  ·  NEET & JEE

A 500 kg boat and a 50 kg man are stationary. Man runs forward at 5 m/s relative to boat. Speed of boat is:

Answer: 5/11 m/s backward.

  • A 0.45 m/s backward
  • B 0.5 m/s backward
  • C 5/11 m/s backward
  • D 5 m/s forward

Correct answer: C. 5/11 m/s backward

Explanation: Man's speed relative to ground = 5 - v<sub>boat</sub>. Momentum conservation: 0 = 50(5 - v<sub>boat</sub>) - 500 v<sub>boat</sub>. 250 = 550 v<sub>boat</sub>. v<sub>boat</sub> = 250/550 = 5/11 m/s backward.

incline surfaceθmgNfmg sinθmg cosθ

Free-body diagram of a block on an incline: weight (mg) resolves into mg sinθ along the slope and mg cosθ into the slope, balanced by the normal force N and friction f.

Concept context

Newton's three laws, friction, circular motion, and free body diagrams.

Read the full Laws of Motion notes →