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⚛️ Physics  ·  Laws of Motion  ·  NEET & JEE

A 5 kg block has force F = 3t N (t in seconds) applied to it on a frictionless surface. Velocity at t=4 s is:

Answer: 4.8 m/s.

  • A 4.8 m/s
  • B 9.6 m/s
  • C 12 m/s
  • D 24 m/s

Correct answer: A. 4.8 m/s

Explanation: a = F/m = 3t/5 = 0.6t. v = integral of 0.6t dt = 0.3t<sup>2.</sup> At t=4: v = 0.3 x 16 = 4.8 m/s.

incline surfaceθmgNfmg sinθmg cosθ

Free-body diagram of a block on an incline: weight (mg) resolves into mg sinθ along the slope and mg cosθ into the slope, balanced by the normal force N and friction f.

Concept context

Newton's three laws, friction, circular motion, and free body diagrams.

Read the full Laws of Motion notes →