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⚛️ Physics  ·  Laws of Motion  ·  NEET & JEE

A 2 kg object moving at 5 m s<sup>-1</sup> collides with and sticks to a stationary 3 kg object. Their common velocity is:

Answer: 2 m s -1.

  • A 1 m s<sup>-1</sup>
  • B 5 m s<sup>-1</sup>
  • C 2.5 m s<sup>-1</sup>
  • D 2 m s<sup>-1</sup>

Correct answer: D. 2 m s<sup>-1</sup>

Explanation: Conserving momentum: (2)(5) = (2 + 3)v, so v = 10/5 = 2 m s<sup>-1</sup>.

incline surfaceθmgNfmg sinθmg cosθ

Free-body diagram of a block on an incline: weight (mg) resolves into mg sinθ along the slope and mg cosθ into the slope, balanced by the normal force N and friction f.

Concept context

Newton's three laws, friction, circular motion, and free body diagrams.

Read the full Laws of Motion notes →