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⚛️ Physics  ·  Laws of Motion  ·  NEET & JEE

A 10 kg block on a rough horizontal surface with mu_k = 0.3. Force needed to keep it moving at constant velocity (g=10):

Answer: 30 N.

  • A 3 N
  • B 15 N
  • C 30 N
  • D 100 N

Correct answer: C. 30 N

Explanation: Kinetic friction fk = mu_k x N = 0.3 x 10 x 10 = 30 N. For constant velocity, applied force = fk = 30 N.

incline surfaceθmgNfmg sinθmg cosθ

Free-body diagram of a block on an incline: weight (mg) resolves into mg sinθ along the slope and mg cosθ into the slope, balanced by the normal force N and friction f.

Concept context

Newton's three laws, friction, circular motion, and free body diagrams.

Read the full Laws of Motion notes →