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⚛️ Physics  ·  Laws of Motion  ·  NEET & JEE

A 0.5 kg ball hits a wall at 10 m/s and bounces back at 10 m/s. Contact time = 0.01 s. Force on ball is:

Answer: 1000 N.

  • A 100 N
  • B 500 N
  • C 1000 N
  • D 2000 N

Correct answer: C. 1000 N

Explanation: F = m x delta_v / delta_t = 0.5 x 20 / 0.01 = 1000 N.

incline surfaceθmgNfmg sinθmg cosθ

Free-body diagram of a block on an incline: weight (mg) resolves into mg sinθ along the slope and mg cosθ into the slope, balanced by the normal force N and friction f.

Concept context

Newton's three laws, friction, circular motion, and free body diagrams.

Read the full Laws of Motion notes →