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⚛️ Physics  ·  Electromagnetic Induction  ·  NEET & JEE

Two coils, P and Q, are placed near each other. When the current in coil P changes at a rate of 5 A/s, an EMF of 0.02 V is induced in coil Q. The mutual inductance between the coils is:

Answer: 4 mH.

  • A 10 mH
  • B 4 mH
  • C 0.1 H
  • D 25 mH

Correct answer: B. 4 mH

Explanation: EMF = M(dI/dt), so M = EMF/(dI/dt) = 0.02/5 = 4 × 10⁻³ H = 4 mH.

EMF is Induced Only While Flux is ChangingΦmagnet approachingmagnet stationary inside coilEMFEMF ≠ 0 (flux changing)EMF = 0 (flux constant)t

As a magnet approaches a coil, flux rises steadily and a constant non-zero EMF is induced (Faraday's law). Once the magnet stops moving, flux stays constant and the induced EMF drops to zero - EMF only exists while flux is actively changing.

Concept context

Faraday's and Lenz's laws, motional EMF, self/mutual inductance, eddy currents, and the AC generator - how a changing magnetic flux creates an electric current.

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