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⚛️ Physics  ·  Electromagnetic Induction  ·  NEET & JEE

The current through a 0.5 H inductor changes steadily from 2 A to 6 A in 0.1 s. The magnitude of the self-induced emf is:

Answer: 20 V.

  • A 10 V
  • B 40 V
  • C 5 V
  • D 20 V

Correct answer: D. 20 V

Explanation: Self-induced emf = L(dI/dt) = 0.5 × (6 - 2)/0.1 = 0.5 × 40 = 20 V.

EMF is Induced Only While Flux is ChangingΦmagnet approachingmagnet stationary inside coilEMFEMF ≠ 0 (flux changing)EMF = 0 (flux constant)t

As a magnet approaches a coil, flux rises steadily and a constant non-zero EMF is induced (Faraday's law). Once the magnet stops moving, flux stays constant and the induced EMF drops to zero - EMF only exists while flux is actively changing.

Concept context

Faraday's and Lenz's laws, motional EMF, self/mutual inductance, eddy currents, and the AC generator - how a changing magnetic flux creates an electric current.

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