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⚛️ Physics  ·  Electromagnetic Induction  ·  NEET & JEE

Mutual inductance M of two coaxial solenoids (inner: n<sub>1</sub> turns/m, area A; outer: n<sub>2</sub> turns/m, length l):

Answer: mu 0 n 1 n 2 Al.

  • A mu<sub>0</sub> n<sub>1</sub> n<sub>2</sub> Al
  • B mu<sub>0</sub> n<sub>1</sub> n<sub>2</sub> A
  • C mu<sub>0</sub> n<sub>1</sub> A/n<sub>2</sub>
  • D mu<sub>0</sub> n<sub>1</sub><sup>2</sup> Al

Correct answer: A. mu<sub>0</sub> n<sub>1</sub> n<sub>2</sub> Al

Explanation: M = mu<sub>0</sub> n<sub>1</sub> n<sub>2</sub> A l (for closely wound coaxial solenoids). Flux linkage from inner to outer = n<sub>2</sub> l x mu<sub>0</sub> n<sub>1</sub> I x A.

EMF is Induced Only While Flux is ChangingΦmagnet approachingmagnet stationary inside coilEMFEMF ≠ 0 (flux changing)EMF = 0 (flux constant)t

As a magnet approaches a coil, flux rises steadily and a constant non-zero EMF is induced (Faraday's law). Once the magnet stops moving, flux stays constant and the induced EMF drops to zero - EMF only exists while flux is actively changing.

Concept context

Faraday's and Lenz's laws, motional EMF, self/mutual inductance, eddy currents, and the AC generator - how a changing magnetic flux creates an electric current.

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