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⚛️ Physics  ·  Electromagnetic Induction  ·  NEET & JEE

A metal disc rotates with angular velocity ω about an axis through its centre, perpendicular to its plane, in a uniform magnetic field B parallel to the axis (Faraday disc dynamo). The EMF induced between the centre and the rim of the disc (radius R) is:

Answer: BωR²/2.

  • A BωR²/2
  • B BωR²
  • C 2BωR²
  • D BωR

Correct answer: A. BωR²/2

Explanation: Treating the disc as made of rotating radial rods, the EMF between centre and rim works out to BωR²/2, the same formula as for a single rotating rod of length R about one end.

EMF is Induced Only While Flux is ChangingΦmagnet approachingmagnet stationary inside coilEMFEMF ≠ 0 (flux changing)EMF = 0 (flux constant)t

As a magnet approaches a coil, flux rises steadily and a constant non-zero EMF is induced (Faraday's law). Once the magnet stops moving, flux stays constant and the induced EMF drops to zero - EMF only exists while flux is actively changing.

Concept context

Faraday's and Lenz's laws, motional EMF, self/mutual inductance, eddy currents, and the AC generator - how a changing magnetic flux creates an electric current.

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