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⚛️ Physics  ·  Electromagnetic Induction  ·  NEET & JEE

A generator coil has a peak emf of 20 V. At an instant when the magnetic flux through the coil is half its maximum value, the magnitude of the induced emf is:

Answer: 17.3 V.

  • A 10.0 V
  • B 20.0 V
  • C 17.3 V
  • D 14.1 V

Correct answer: C. 17.3 V

Explanation: If the flux is half its maximum value, cos&theta; = 1/2 so &theta; = 60&deg;. The emf magnitude is E<sub>0</sub> sin&theta; = 20 &times; sin60&deg; = 17.3 V.

EMF is Induced Only While Flux is ChangingΦmagnet approachingmagnet stationary inside coilEMFEMF ≠ 0 (flux changing)EMF = 0 (flux constant)t

As a magnet approaches a coil, flux rises steadily and a constant non-zero EMF is induced (Faraday's law). Once the magnet stops moving, flux stays constant and the induced EMF drops to zero - EMF only exists while flux is actively changing.

Concept context

Faraday's and Lenz's laws, motional EMF, self/mutual inductance, eddy currents, and the AC generator - how a changing magnetic flux creates an electric current.

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