Zaymiey

⚛️ Physics  ·  Electromagnetic Induction  ·  NEET & JEE

A conducting rod of length 0.5 m moves at 4 m/s perpendicular to a magnetic field of 0.8 T on rails connected by a 2 Ω resistor. The magnetic force opposing the motion is:

Answer: 0.32 N.

  • A 0.16 N
  • B 0.32 N
  • C 0.64 N
  • D 1.28 N

Correct answer: B. 0.32 N

Explanation: The emf is Blv = 0.8 × 0.5 × 4 = 1.6 V. Current is 1.6/2 = 0.8 A. Hence F = BIl = 0.8 × 0.8 × 0.5 = 0.32 N.

EMF is Induced Only While Flux is ChangingΦmagnet approachingmagnet stationary inside coilEMFEMF ≠ 0 (flux changing)EMF = 0 (flux constant)t

As a magnet approaches a coil, flux rises steadily and a constant non-zero EMF is induced (Faraday's law). Once the magnet stops moving, flux stays constant and the induced EMF drops to zero - EMF only exists while flux is actively changing.

Concept context

Faraday's and Lenz's laws, motional EMF, self/mutual inductance, eddy currents, and the AC generator - how a changing magnetic flux creates an electric current.

Read the full Electromagnetic Induction notes →