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⚛️ Physics  ·  Electromagnetic Induction  ·  NEET & JEE

A conducting rod of length 0.5 m moves at 4 m/s perpendicular to a 0.8 T magnetic field. The circuit resistance is 2 Ω. The mechanical power required to maintain constant speed is:

Answer: 1.28 W.

  • A 1.28 W
  • B 0.64 W
  • C 2.56 W
  • D 5.12 W

Correct answer: A. 1.28 W

Explanation: Induced emf = Blv = 1.6 V and current = 1.6/2 = 0.8 A. Mechanical power equals electrical power lost as heat: P = I<sup>2</sup>R = 0.8<sup>2</sup> &times; 2 = 1.28 W.

EMF is Induced Only While Flux is ChangingΦmagnet approachingmagnet stationary inside coilEMFEMF ≠ 0 (flux changing)EMF = 0 (flux constant)t

As a magnet approaches a coil, flux rises steadily and a constant non-zero EMF is induced (Faraday's law). Once the magnet stops moving, flux stays constant and the induced EMF drops to zero - EMF only exists while flux is actively changing.

Concept context

Faraday's and Lenz's laws, motional EMF, self/mutual inductance, eddy currents, and the AC generator - how a changing magnetic flux creates an electric current.

Read the full Electromagnetic Induction notes →