When batteries of EMF E 1 and E 2 (E 1 > E 2 ) are connected in series opposing (positive terminals facing each other):

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When batteries of EMF E₁ and E₂ (E₁ > E₂) are connected in series opposing (positive terminals facing each other):

Answer: Net EMF = E₁-E₂.

A Net EMF = E₁+E₂
B Net EMF = E₁-E₂
C Net EMF = 0
D Net EMF = E₁ x E₂

Correct answer: B. Net EMF = E₁-E₂

Explanation: Series opposing (aiding against each other): net EMF = E₁ - E₂ (EMFs subtract).

In series, the same current flows through both resistors; in parallel, the current splits between branches and the voltage across each resistor is the same.

Concept context

Ohm's law, resistors, Kirchhoff's laws, Wheatstone bridge, and cells.

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When batteries of EMF E1 and E2 (E1 > E2) are connected in series opposing (positive terminals facing each other):

Concept context

More Current Electricity questions

When batteries of EMF E₁ and E₂ (E₁ > E₂) are connected in series opposing (positive terminals facing each other):