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⚛️ Physics  ·  Current Electricity  ·  NEET & JEE

Two identical cells, each of emf 2 V and internal resistance 1 Ω, are connected in parallel with the same polarity to a 4 Ω resistor. What current flows through the resistor?

Answer: 0.44 A.

  • A 0.25 A
  • B 0.44 A
  • C 0.50 A
  • D 0.67 A

Correct answer: B. 0.44 A

Explanation: The parallel combination has emf 2 V and internal resistance 1/2 Ω. Hence I = 2/(4 + 0.5) = 0.44 A.

SeriesbatteryR1R2I (same in R1, R2)ParallelbatteryR1R2I1I2

In series, the same current flows through both resistors; in parallel, the current splits between branches and the voltage across each resistor is the same.

Concept context

Ohm's law, resistors, Kirchhoff's laws, Wheatstone bridge, and cells.

Read the full Current Electricity notes →