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⚛️ Physics  ·  Current Electricity  ·  NEET & JEE

Two cells, each of emf 2 V and internal resistance 1 Ω, are connected in series across a 2 Ω resistor. The current is:

Answer: 1 A.

  • A 0.5 A
  • B 1 A
  • C 2 A
  • D 4 A

Correct answer: B. 1 A

Explanation: I = total emf/total resistance = 4/(1 + 1 + 2) = 1 A.

SeriesbatteryR1R2I (same in R1, R2)ParallelbatteryR1R2I1I2

In series, the same current flows through both resistors; in parallel, the current splits between branches and the voltage across each resistor is the same.

Concept context

Ohm's law, resistors, Kirchhoff's laws, Wheatstone bridge, and cells.

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