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⚛️ Physics  ·  Current Electricity  ·  NEET & JEE

Power dissipated in a resistor R carrying current I:

Answer: I 2R.

  • A IR
  • B I<sup>2R</sup>
  • C IR<sup>2</sup>
  • D I<sup>2</sup>/R

Correct answer: B. I<sup>2R</sup>

Explanation: P = I<sup>2</sup> R = V<sup>2</sup>/R = IV. All three forms are equivalent. P = I<sup>2</sup> R is most direct.

SeriesbatteryR1R2I (same in R1, R2)ParallelbatteryR1R2I1I2

In series, the same current flows through both resistors; in parallel, the current splits between branches and the voltage across each resistor is the same.

Concept context

Ohm's law, resistors, Kirchhoff's laws, Wheatstone bridge, and cells.

Read the full Current Electricity notes →