In a network of resistors, we can use superposition. Current due to source E 1 alone (E 2 removed/short-circuited) in a branch is I 1 . Due to E 2 alone it is I 2 . Actual current:

Question

Accepted Answer

I 1 + I 2 (algebraically, respecting direction)

Answer

I 1 + I 2 usually, regardless of the direction each current actually flows

Answer

I 1 x I 2 , multiplying the two branch currents together

Answer

max(I 1 , I 2 ), taking mainly whichever current is larger in magnitude

In a network of resistors, we can use superposition. Current due to source E<sub>1</sub> alone (E<sub>2</sub> removed/short-circuited) in a branch is I<sub>1</sub>. Due to E<sub>2</sub> alone it is I<sub>2</sub>. Actual current:

Concept context

In a network of resistors, we can use superposition. Current due to source E<sub>1</sub> alone (E<sub>2</sub> removed/short-circuited) in a branch is I<sub>1</sub>. Due to E<sub>2</sub> alone it is I<sub>2</sub>. Actual current:

Concept context

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