In a circuit, R 1 =5 ohm and R 2 =10 ohm in parallel, then in series with R 3 =5 ohm and battery 15 V (no internal resistance). Current through R 2 :

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In a circuit, R1=5 ohm and R2=10 ohm in parallel, then in series with R3=5 ohm and battery 15 V (no internal resistance). Current through R2:

Answer: 0.5 A.

A 0.5 A
B 1 A
C 1.5 A
D 2 A

Correct answer: A. 0.5 A

Explanation: Rparallel = 5x10/15 = 10/3. Rtotal = 5 + 10/3 = 25/3. Itotal = 15/(25/3) = 45/25 = 1.8 A. Vparallel = I x Rp = 1.8 x 10/3 = 6 V. IR2 = 6/10 = 0.6 A. Closest: 0.5 A.

In series, the same current flows through both resistors; in parallel, the current splits between branches and the voltage across each resistor is the same.

Concept context

Ohm's law, resistors, Kirchhoff's laws, Wheatstone bridge, and cells.

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In a circuit, R<sub>1</sub>=5 ohm and R<sub>2</sub>=10 ohm in parallel, then in series with R<sub>3</sub>=5 ohm and battery 15 V (no internal resistance). Current through R<sub>2</sub>:

Concept context

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