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⚛️ Physics  ·  Current Electricity  ·  NEET & JEE

A wire of resistance 16 Ω is cut into four equal pieces. Two pieces are connected in parallel to form one branch and the other two are connected in parallel to form a second branch. The two branches are then connected in series across an 8 V source. What is the total power consumed?

Answer: 16 W.

  • A 8 W
  • B 16 W
  • C 24 W
  • D 32 W

Correct answer: B. 16 W

Explanation: Each piece has resistance 16/4 = 4 &Omega;. Each parallel pair has equivalent resistance 2 &Omega;. The two branches in series give 4 &Omega;. Therefore P = V<sup>2</sup>/R = 8<sup>2</sup>/4 = 16 W.

SeriesbatteryR1R2I (same in R1, R2)ParallelbatteryR1R2I1I2

In series, the same current flows through both resistors; in parallel, the current splits between branches and the voltage across each resistor is the same.

Concept context

Ohm's law, resistors, Kirchhoff's laws, Wheatstone bridge, and cells.

Read the full Current Electricity notes →