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⚛️ Physics  ·  Current Electricity  ·  NEET & JEE

A copper conductor contains 8.5 &times; 10<sup>28</sup> free electrons per m<sup>3</sup>. If a current of 1.36 A flows through a cross-sectional area of 1.0 mm<sup>2</sup>, what is the electron drift speed? Take e = 1.6 &times; 10<sup>-19</sup> C.

Answer: 1.0 10 -4 m s -1.

  • A 1.0 &times; 10<sup>-4</sup> m s<sup>-1</sup>
  • B 1.0 &times; 10<sup>-3</sup> m s<sup>-1</sup>
  • C 1.0 &times; 10<sup>-2</sup> m s<sup>-1</sup>
  • D 1.0 &times; 10<sup>-1</sup> m s<sup>-1</sup>

Correct answer: A. 1.0 &times; 10<sup>-4</sup> m s<sup>-1</sup>

Explanation: Using I = neAv<sub>d</sub>, v<sub>d</sub> = I/(neA) = 1.36/[8.5 &times; 10<sup>28</sup> &times; 1.6 &times; 10<sup>-19</sup> &times; 10<sup>-6</sup>] = 1.0 &times; 10<sup>-4</sup> m s<sup>-1</sup>.

SeriesbatteryR1R2I (same in R1, R2)ParallelbatteryR1R2I1I2

In series, the same current flows through both resistors; in parallel, the current splits between branches and the voltage across each resistor is the same.

Concept context

Ohm's law, resistors, Kirchhoff's laws, Wheatstone bridge, and cells.

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