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⚛️ Physics  ·  Current Electricity  ·  NEET & JEE

A cell of emf 12 V and internal resistance 1 Ω is connected to 5 Ω and 10 Ω resistors in parallel. What current flows through the 10 Ω resistor?

Answer: 0.923 A.

  • A 2.77 A
  • B 1.38 A
  • C 1.85 A
  • D 0.923 A

Correct answer: D. 0.923 A

Explanation: The external resistance is 5 × 10/(5 + 10) = 10/3 Ω. Total current is 12/(1 + 10/3) = 36/13 A. The terminal voltage is (36/13)(10/3) = 120/13 V, so current through 10 Ω is 12/13 = 0.923 A.

SeriesbatteryR1R2I (same in R1, R2)ParallelbatteryR1R2I1I2

In series, the same current flows through both resistors; in parallel, the current splits between branches and the voltage across each resistor is the same.

Concept context

Ohm's law, resistors, Kirchhoff's laws, Wheatstone bridge, and cells.

Read the full Current Electricity notes →