Using E n = −13.6/n² eV, the ground-state (n = 1) energy of hydrogen is:

Using E n = −13.6/n² eV, the…

Answer: −13.6 eV.

A −13.6 eV
B −3.4 eV
C 0 eV
D +13.6 eV

Correct answer: A. −13.6 eV

Explanation: E<sub>1</sub> = −13.6/1² = −13.6 eV.

Comparison of the Thomson model and the Rutherford model of the atom: in the Thomson plum pudding model alpha particles pass almost straight through a diffuse positive sphere, while in the Rutherford model a concentrated central nucleus deflects some alpha particles through large angles, with the lower panels showing the alpha particle source and gold foil and the observed result of wide-angle scattering

The Geiger–Marsden alpha-scattering result: a few alpha particles bounce back at large angles, which rules out Thomson’s diffuse model and demands a tiny, massive, positively charged nucleus. Image: Kurzon, CC BY 3.0, via Wikimedia Commons.

Concept context

Thomson's plum-pudding model, Rutherford's nuclear model from alpha-scattering, Bohr's postulates and hydrogen spectrum, spectral series (Lyman to Pfund), Rydberg formula, and limitations of each model.

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Using E<sub>n</sub> = −13.6/n² eV, the ground-state (n = 1) energy of hydrogen is:

Concept context

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