The series limit (shortest wavelength) of the Lyman series is the transition from n = ∞ to n =:

The series limit (shortest wavelength)…

Answer: 1.

Correct answer: A. 1

Explanation: The Lyman series always ends on n = 1, so its limit is ∞ → 1.

Comparison of the Thomson model and the Rutherford model of the atom: in the Thomson plum pudding model alpha particles pass almost straight through a diffuse positive sphere, while in the Rutherford model a concentrated central nucleus deflects some alpha particles through large angles, with the lower panels showing the alpha particle source and gold foil and the observed result of wide-angle scattering

The Geiger–Marsden alpha-scattering result: a few alpha particles bounce back at large angles, which rules out Thomson’s diffuse model and demands a tiny, massive, positively charged nucleus. Image: Kurzon, CC BY 3.0, via Wikimedia Commons.

Concept context

Thomson's plum-pudding model, Rutherford's nuclear model from alpha-scattering, Bohr's postulates and hydrogen spectrum, spectral series (Lyman to Pfund), Rydberg formula, and limitations of each model.

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The series limit (shortest wavelength) of the Lyman series is the transition from n = ∞ to n =:

Concept context

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