⚛️ Physics · Atoms · NEET & JEE

For hydrogen, compare the photon frequencies produced by transitions n = 6 to n = 2 and n = 3 to n = 2. What is the ratio ν<sub>6→2</sub>/ν<sub>3→2</sub>?

Answer: 8/5.

A 4/5
B 5/4
C 5/8
D 8/5

Correct answer: D. 8/5

Explanation: Photon frequency is proportional to the energy difference. The ratio is [(1/4 - 1/36)/(1/4 - 1/9)] = (2/9)/(5/36) = 8/5.

Comparison of the Thomson model and the Rutherford model of the atom: in the Thomson plum pudding model alpha particles pass almost straight through a diffuse positive sphere, while in the Rutherford model a concentrated central nucleus deflects some alpha particles through large angles, with the lower panels showing the alpha particle source and gold foil and the observed result of wide-angle scattering

The Geiger–Marsden alpha-scattering result: a few alpha particles bounce back at large angles, which rules out Thomson’s diffuse model and demands a tiny, massive, positively charged nucleus. Image: Kurzon, CC BY 3.0, via Wikimedia Commons.

Concept context

Thomson's plum-pudding model, Rutherford's nuclear model from alpha-scattering, Bohr's postulates and hydrogen spectrum, spectral series (Lyman to Pfund), Rydberg formula, and limitations of each model.

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For hydrogen, compare the photon frequencies produced by transitions n = 6 to n = 2 and n = 3 to n = 2. What is the ratio &nu;<sub>6&rarr;2</sub>/&nu;<sub>3&rarr;2</sub>?

Concept context

More Atoms questions

For hydrogen, compare the photon frequencies produced by transitions n = 6 to n = 2 and n = 3 to n = 2. What is the ratio ν<sub>6→2</sub>/ν<sub>3→2</sub>?