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📐 Mathematics  ·  Vector Algebra  ·  JEE

Using a.b = |a||b|cos(theta): angle between a = 3i+4j and b = 4i+3j satisfies:

Answer: cos(theta) = 24/25.

  • A cos(theta) = 0
  • B cos(theta) = 7/25
  • C cos(theta) = 1
  • D cos(theta) = 24/25

Correct answer: D. cos(theta) = 24/25

Explanation: Dot product: a·b = 3(4)+4(3) = 12+12 = 24. Magnitudes: |a| = √(9+16) = 5, |b| = √(16+9) = 5. cosθ = 24/(5×5) = 24/25. Answer: cosθ = 24/25.

xya (4,1)b (2,3)a + b (6,4)

Triangle law of vector addition: placing vector b at the head of vector a, the diagonal from the start to the final head gives the resultant a + b.

Concept context

Vectors, dot product, cross product, and geometric applications

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