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📐 Mathematics  ·  Vector Algebra  ·  JEE

The vector equation of the plane through three points with position vectors a, b, c is:

Answer: r = a + lambda*(b-a) + mu*(c-a).

  • A r . (b x c) = 0, a condition for a plane through the origin
  • B r = (a+b+c)/3, just the centroid point
  • C r = lambda*a + mu*b, missing the third point c
  • D r = a + lambda*(b-a) + mu*(c-a)

Correct answer: D. r = a + lambda*(b-a) + mu*(c-a)

Explanation: The plane through a, b, c contains two direction vectors (b−a) and (c−a). Parametric form: r = a + λ(b−a) + μ(c−a), where λ,μ∈ℝ. When λ=μ=0: r=a; λ=1,μ=0: r=b; λ=0,μ=1: r=c. Answer: r = a + λ(b−a) + μ(c−a).

xya (4,1)b (2,3)a + b (6,4)

Triangle law of vector addition: placing vector b at the head of vector a, the diagonal from the start to the final head gives the resultant a + b.

Concept context

Vectors, dot product, cross product, and geometric applications

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