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📐 Mathematics  ·  Vector Algebra  ·  JEE

The resultant of two equal vectors of magnitude F at angle theta has magnitude:

Answer: 2F cos(theta/2).

  • A 2F
  • B F cos(theta)
  • C F sin(theta)
  • D 2F cos(theta/2)

Correct answer: D. 2F cos(theta/2)

Explanation: |R|<sup>2</sup> = F<sup>2</sup>+F<sup>2</sup>+2F<sup>2</sup> cos(theta) = 2F<sup>2</sup>(1+cos(theta)) = 4F<sup>2</sup> cos<sup>2</sup>(theta/2). So |R| = 2F cos(theta/2).

xya (4,1)b (2,3)a + b (6,4)

Triangle law of vector addition: placing vector b at the head of vector a, the diagonal from the start to the final head gives the resultant a + b.

Concept context

Vectors, dot product, cross product, and geometric applications

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