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📐 Mathematics  ·  Vector Algebra  ·  JEE

The area of triangle with vertices A(1,0,0), B(0,1,0), C(0,0,1) is:

Answer: sqrt(3)/2.

  • A 1/2
  • B 1
  • C sqrt(3)
  • D sqrt(3)/2

Correct answer: D. sqrt(3)/2

Explanation: AB = B−A = (−1,1,0), AC = C−A = (−1,0,1). Cross product AB×AC = |i j k; −1 1 0; −1 0 1| = (1,1,1). |AB×AC| = √3. Area = ½√3 = √3/2. Answer: √3/2.

xya (4,1)b (2,3)a + b (6,4)

Triangle law of vector addition: placing vector b at the head of vector a, the diagonal from the start to the final head gives the resultant a + b.

Concept context

Vectors, dot product, cross product, and geometric applications

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