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📐 Mathematics  ·  Vector Algebra  ·  JEE

If a + b + c = 0, then a.b + b.c + c.a =

Answer: -(|a| 2 +|b| 2 +|c| 2 )/2.

  • A 0
  • B (|a|<sup>2</sup>+|b|<sup>2</sup>+|c|<sup>2</sup>)/2
  • C -(|a|<sup>2</sup>+|b|<sup>2</sup>+|c|<sup>2</sup>)/2
  • D |a|<sup>2</sup>+|b|<sup>2</sup>+|c|<sup>2</sup>

Correct answer: C. -(|a|<sup>2</sup>+|b|<sup>2</sup>+|c|<sup>2</sup>)/2

Explanation: |a+b+c|<sup>2</sup> = 0. Expanding: |a|<sup>2</sup>+|b|<sup>2</sup>+|c|<sup>2</sup>+2(a.b+b.c+c.a) = 0. So a.b+b.c+c.a = -(|a|<sup>2</sup>+|b|<sup>2</sup>+|c|<sup>2</sup>)/2.

xya (4,1)b (2,3)a + b (6,4)

Triangle law of vector addition: placing vector b at the head of vector a, the diagonal from the start to the final head gives the resultant a + b.

Concept context

Vectors, dot product, cross product, and geometric applications

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